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- % --- ------------------------------------------------------------------
- % --- English-style Date Macros for LaTeX, version 1.00--0.
- % --- ------------------------------------------------------------------
- %
- % --- \today (replaces American-style macro of same name) generates
- % --- today's date in the form Thursday 4th October 1066.
- % --- The `th' is raised, reduced in size and underlined in the
- % --- same font style (family) as the rest of the date.
- %
- % --- \st generates a raised, reduced, underlined `st', as in 1st.
- % --- \nd generates a raised, reduced, underlined `nd', as in 2nd.
- % --- \rd generates a raised, reduced, underlined `rd', as in 3rd.
- % --- \th generates a raised, reduced, underlined `th', as in 4th.
- %
- % --- \dayofweek generates the day of the week, based on TeX's values
- % --- of \day, \month and \year.
- %
- % --- \phaseofmoon generates the current phase of the moon, again based
- % --- on TeX's values for \day, \month and \year.
- %
- % --- ------------------------------------------------------------------
- % --- Adrian F. Clark (alien@uk.ac.essex.ese) 26-Oct-1988 10:05:50
- % --- ------------------------------------------------------------------
-
- % --- Counters. Note that we use the same registers as TeX holds other
- % --- things in (e.g., \count0 holds the page number). This requires
- % --- that \@savestyle, \@setstyle, \dayofweek and \phaseofmoon perform
- % --- all their register manipulations within a group. This may seem
- % --- a bit messy, but it saves having eight registers permanently set
- % --- aside just for date calculation.
-
- \def\@cent{\count0 } % century number (1979 == 20)
- \def\@diy{\count1 } % day in the year
- \def\@dow{\count2 } % gets day of the week
- \def\@epact{\count3 } % age of the moon on Jan. 1
- \def\@golden{\count4 } % Moon's golden number
- \def\@leap{\count5 } % leap year fingaler
- \def\@x{\count6 } % temp register
- \def\@y{\count7 } % another temp register
-
-
- % --- A replacement for the ``plain'' TeX and LaTeX \today macro, to
- % --- to output the date in English-style.
- % --- They ensure the smaller text comes out in the right font by saving
- % --- the font family before reducing the size, then restoring it. (This
- % --- was suggested by Leslie Lamport.) Of course, it requires that the
- % --- font in use when today is invoked has a sensible family.
-
- \def\@up#1{{\@savestyle\thinspace$^{\underline{\hbox{%
- \scriptsize\@setstyle#1\fam=-1 }}}$}}
- \def\st{\@up{st}}
- \def\nd{\@up{nd}}
- \def\rd{\@up{rd}}
- \def\th{\@up{th}}
-
- % --- Macros to save and restore the font family.
-
- \def\@savestyle{\count0=\the\fam}
- \def\@setstyle{\ifcase\count0\rm\or\mit\or\cal\or\rm% what's family 3?
- \or\it\or\sl\or\bf\or\tt\fi}
-
- % --- The date, English style (e.g. Thursday 4th October 1066).
-
- \def\today{\dayofweek\ \number\day\ifcase\day
- \or\st\or\nd\or\rd\or\th\or\th\or\th\or\th\or\th\or\th\or\th
- \or\th\or\th\or\th\or\th\or\th\or\th\or\th\or\th\or\th\or\th
- \or\st\or\nd\or\rd\or\th\or\th\or\th\or\th\or\th\or\th\or\th\or\st\fi
- \space\ifcase\month\or January\or February\or March\or April\or May\or
- June\or July\or August\or September\or October\or November\or December\fi
- \space\number\year}
-
- % --- The day of the week ("Sunday", etc.) is inserted into the text
- % --- by \dayofweek. (This uses registers \@dow, \@leap, \@x and \@y.)
- % --- I acquired this from elsewhere; I don't know who wrote it.
-
- \def\dayofweek{{%
- % leap = year + (month - 14)/12;
- \@leap=\month \advance\@leap by -14 \divide\@leap by 12
- \advance\@leap by \year
- % dow = (13 * (month + 10 - (month + 10)/13*12) - 1)/5
- \@dow=\month \advance\@dow by 10
- \@y=\@dow \divide\@y by 13 \multiply\@y by 12
- \advance\@dow by -\@y \multiply\@dow by 13
- \advance\@dow by -1 \divide\@dow by 5
- % dow += day + 77 + 5 * (leap % 100)/4
- \advance\@dow by \day \advance\@dow by 77
- \@x=\@leap \@y=\@x \divide\@y by 100 \multiply\@y by 100 \advance\@x by -\@y
- \multiply\@x by 5 \divide\@x by 4 \advance\@dow by \@x
- % dow += leap / 400
- \@x=\@leap \divide\@x by 400 \advance\@dow by \@x
- % dow -= leap / 100 * 2;
- % dow = (dow % 7)
- \@x=\@leap \divide\@x by 100 \multiply\@x by 2 \advance\@dow by -\@x
- \@x=\@dow \divide\@x by 7 \multiply\@x by 7 \advance\@dow by -\@x
- \ifcase\@dow Sunday\or Monday\or Tuesday\or Wednesday\or
- Thursday\or Friday\or Saturday\fi}}
- %
- % --- Likewise, \phaseofmoon inserts the phase of the moon into the
- % --- text. This was written by the same person as \dayofweek.
- % --- The routine calculates the year's epact (the age of the moon on Jan 1.),
- % --- adds this to the number of days in the year, and calculates the phase
- % --- of the moon for this date. It returns the phase as a string, e.g.,
- % --- "new", "full", etc.
- %
- % --- In the algorithm:
- % --- diy is the day of the year - 1 (i.e., Jan 1 is day 0).
- % --- golden is the number of the year in the Mentonic cycle, used to
- % --- determine the position of the calender moon.
- % --- epact is the age of the calender moon (in days) at the beginning
- % --- of the year. To calculate epact, two century-based
- % --- corrections are applied:
- % --- Gregorian: (3 * cent)/4 - 12
- % --- is the number of years such as 1700, 1800 when
- % --- leap year was not held.
- % --- Clavian: (((8 * cent) + 5) / 25) - 5
- % --- is a correction to the Mentonic cycle of about
- % --- 8 days every 2500 years. Note that this will
- % --- overflow 16 bits in the year 409600. Beware.
- % --- The algorithm is accurate for the Gregorian calender only.
- %
- % --- The magic numbers used in the phase calculation are:
- % --- 29.5 The moon's period in days.
- % --- 177 29.5 scaled by 6
- % --- 22 (29.5 / 8) scaled by 6 (this gets the phase)
- % --- 11 ((29.5 / 8) / 2) scaled by 6
- %
- % --- Theoretically, this should yield a number in the range 0 .. 7. However,
- % --- two days per year, things don't work out too well.
- %
- % --- Epact is calculated by the algorithm given in Knuth vol. 1 (Calculation
- % --- of Easter). See also the article on Calenders in the Encyclopaedia
- % --- Britannica and Knuth's algorithm in CACM April 1962, page 209.
- %
- \def\phaseofmoon{{%
- \@diy=\day \advance\@diy by \ifcase\month % Jan 1 == 0
- -1\or -1\or 30\or 58\or 89\or 119\or 150\or % Jan .. Jun
- 180\or 211\or 241\or 272\or 303\or 333\fi % Jul .. Dec
- % if ((month > 2) && ((year % 4 == 0) &&
- % ((year % 400 == 0) || (year % 100 != 0))))
- % diy++; /* Leapyear fixup */
- \ifnum \month>2
- \@x=\year \@y=\@x \divide\@y by 4 \multiply\@y by 4 \advance\@x by -\@y
- \ifnum \@x=0 % month > 2 and maybe leapyear
- \@x=\year \@y=\@x \divide\@y by 400
- \multiply\@y by 400 \advance\@x by -\@y
- \ifnum \@x=0 % 2000 is a leap year
- \advance\@diy by 1 % so it's one day later
- \else % not 2000, check other '00's
- \@x=\year \@y=\@x \divide\@y by 100
- \multiply\@y by 100 \advance\@x by -\@y
- \ifnum \@x>0 % not some other '00' year
- \advance\@diy by 1 % it's still one day later
- \fi % not odd century
- \fi % not 2000-type century
- \fi % not leapish year
- \fi % not march or later
- % cent = (year / 100) + 1; /* Century number */
- % golden = (year % 19) + 1; /* Golden number */
- \@cent=\year \divide\@cent by 100 \advance\@cent by 1
- \@golden=\year
- \@y=\year \divide\@y by 19 \multiply\@y by 19 \advance\@golden by -\@y
- \advance\@golden by 1
- % epact = ((11 * golden) + 20 /* Golden number */
- % + (((8 * cent) + 5) / 25) - 5 /* 400 year cycle */
- % - (((3 * cent) / 4) - 12)) % 30; /* Leap year correction */
- \@epact=11 \multiply\@epact by \@golden
- \advance\@epact by 20
- \@x=8 \multiply\@x by \@cent \advance\@x by 5
- \divide\@x by 25 \advance\@x by -5
- \advance\@epact by \@x
- \@x=3 \multiply\@x by \@cent \divide\@x by 4 \advance\@x by -12
- \advance\@epact by -\@x
- \@y=\@epact \divide\@y by 30 \multiply\@y by 30 \advance\@epact by -\@y
- % if (epact <= 0)
- % epact += 30; /* Age range is 1 .. 30 */
- % if ((epact == 25 && golden > 11) || epact == 24)
- % epact++;
- \ifnum \@epact<0
- \advance\@epact by 30
- \fi
- \ifnum \@epact=25
- \ifnum \@golden>11
- \advance \@epact by 1
- \fi
- \else
- \ifnum \@epact=24
- \advance \@epact by 1
- \fi
- \fi
- %
- % --- Calculate the phase, using the magic numbers defined above.
- % --- Note that phase may be equal to 8 (== 0) on two days of the year
- % --- due to the way the algorithm was implemented.
- % --- phase = (((((diy + epact) * 6) + 11) % 177) / 22) & 7;
- %
- \@x=\@diy \advance\@x by \@epact \multiply\@x by 6 \advance\@x by 11
- \@y=\@x \divide\@y by 177 \multiply\@y by 177 \advance\@x by -\@y
- \divide\@x by 22
- \ifcase\@x new\or waxing crescent\or in its first quarter\or
- waxing gibbous\or full\or waning gibbous\or
- in its last quarter\or waning crescent\or new\fi}}
-
- % --- End of ukdate.sty
-